Input Format
The first line contains  space-separated integers denoting the respective , and  on which the book was actually returned.
The second line contains  space-separated integers denoting the respective , and  on which the book was expected to be returned (due date).
Constraints

Output Format
Print a single integer denoting the library fine for the book received as input.

### Problem solution in Bash programming language

read d_act m_act y_act

if (( y_act > y_exp )); then
echo 10000
elif (( y_act == y_exp )); then
if (( m_act > m_exp )); then
echo $(( 500 * (m_act - m_exp) )) elif (( m_act == m_exp )); then if (( d_act > d_exp )); then echo$(( 15 * (d_act - d_exp) ))
else
echo 0
fi
else
echo 0
fi
else
echo 0
fi

### Problem solution in c++ programming language.

#include <iostream>
using namespace std;

int main(int argc, const char* args[]){
int actualDay;
int actualMonth;
int actualYear;
int expectedDay;
int expectedMonth;
int expectedYear;

// Actual return date
cin >> actualDay;
cin >> actualMonth;
cin >> actualYear;

// Expected return date
cin >> expectedDay;
cin >> expectedMonth;
cin >> expectedYear;

int fine = 0;

// Returned within the current year:
if(expectedYear == actualYear){
if(expectedMonth < actualMonth){
// Returned 1+ months late in current year
fine = (actualMonth - expectedMonth) * 500;
}
else if( (expectedMonth == actualMonth)
&& (expectedDay < actualDay) ){
// Returned 1+ days late within the current month
fine = (actualDay - expectedDay) * 15;
}
// Else it is implied that the book was returned early
}
else if(expectedYear < actualYear){
// Returned 1+ years late
fine = 10000;
}
// Else it is implied that the book was returned 1+ years early

cout << fine << endl;
}

### Problem solution in Java programming language.

import java.util.*;

class BookReturnDate{
public int day;
public int month;
public int year;

BookReturnDate(int day, int month, int year){
this.day = day;
this.month = month;
this.year = year;
}
}

public class Solution {

public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
BookReturnDate actual = new BookReturnDate(scan.nextInt(), scan.nextInt(),scan.nextInt());
BookReturnDate expected = new BookReturnDate(scan.nextInt(), scan.nextInt(),scan.nextInt());
scan.close();

int fine = 0;

// Returned within the current year:
if(expected.year == actual.year){
// Returned 1+ months late in current year
if(expected.month < actual.month){
fine = (actual.month - expected.month) * 500;
}
// Returned 1+ days late within the current month
else if( (expected.month == actual.month)
&& (expected.day < actual.day) ){
fine = (actual.day - expected.day) * 15;
}
// Else it is implied that the book was returned early
}
else if(expected.year < actual.year){
// Returned 1+ years late
fine = 10000;
}
// Else it is implied that the book was returned 1+ years early

System.out.println(fine);

}
}

### Problem solution in Python programming language.

n = input()
x = list(map(int, n.split()))
m = input()
y = list(map(int, m.split()))
z=0
if y[2] < x[2]:
z = 10000
elif y[2] == x[2]:
if y[1] < x[1]:
z = 500*(x[1]-y[1])
elif y[0] < x[0]:
z = 15*(x[0]-y[0])

print(z)